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WAP to check a given number is even or odd

C++ Code Example — Conditional Programs

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WAP to check a given number is even or odd

Objective

Write a C++ program to check if a given number is even or odd.

Algorithm / Approach

  1. Read an integer a.
  2. Use the modulo operator: if (a % 2 == 0).
  3. If true, the number is Even.
  4. Otherwise, the number is Odd.
main.cpp 
#include<iostream>
using namespace std;
int main() {
 int a;
 cout<<"Enter Value for A: ";
 cin>>a;
 if(a%2==0)
  cout<< a<<" IS EVEN NO.\n";
 else
  cout<< a<<" IS ODD NO.\n";
return 0;
}

Expected Output

Enter Value for A: 12
12 IS EVEN NO.

Explanation of the Program

  • The Modulo operator (%) calculates the remainder of division.
  • Because every even number is perfectly divisible by 2, dividing an even number by 2 will always result in a remainder of exactly 0. This makes number % 2 == 0 the universal test for even numbers.

Complexity

Time Complexity O(1)
Space Complexity O(1)
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